(k-1)x^2+2kx+(k^2+4k+3)=0

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Solution for (k-1)x^2+2kx+(k^2+4k+3)=0 equation: 


Simplifying
(k + -1) * x2 + 2kx + (k2 + 4k + 3) = 0

Reorder the terms:
(-1 + k) * x2 + 2kx + (k2 + 4k + 3) = 0

Reorder the terms for easier multiplication:
x2(-1 + k) + 2kx + (k2 + 4k + 3) = 0
(-1 * x2 + k * x2) + 2kx + (k2 + 4k + 3) = 0

Reorder the terms:
(kx2 + -1x2) + 2kx + (k2 + 4k + 3) = 0
(kx2 + -1x2) + 2kx + (k2 + 4k + 3) = 0

Reorder the terms:
kx2 + -1x2 + 2kx + (3 + 4k + k2) = 0

Remove parenthesis around (3 + 4k + k2)
kx2 + -1x2 + 2kx + 3 + 4k + k2 = 0

Reorder the terms:
3 + 4k + 2kx + kx2 + k2 + -1x2 = 0

Solving
3 + 4k + 2kx + kx2 + k2 + -1x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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